Question

The power series solution of the Initial-Value Problem (IVP) (x² + 1)yl + xy + 2xy = 0 y(0) = 2 is given by y(0) = 3 4 13 325 2 y=2(1 + + :). 2 + + 3 20 6 2 2125 y= 2 + 3x + +. 6 2 4 23 3.25 y = 32 =3(< + + -) +2 (1 + + :) 3 20 6 2 7.23 21.25 y= 2 + x + + + +... 6 2 4 None them

Answer 1

x=0 is ordinary point so series solution is

y=$\sum$$^{_{}}$an x^n is solution

Getting y' and y" and put in Differential equation and solving using given condition y(0)=2 we get a0=2 and y'(0)=3 we get a1=3 and solution we get is option (i)