Question

Systems of Equations: 3x + y = 6 2x-2y=4 Substitution: Elimination: Solve 1 equation for 1 variable. Find opposite coefficients for 1 variable. Rearrange. Multiply equation(s) by constant(s). Plug into 2nd equation Add equations together (lose 1 variable). Solve for the other variable. Solve for variable. Then plug answer back into an original equation to solve for the 2nd variable. y = 6 -- 3x solve 1" equation for y 6x +2y = 12 multiply 1" equation by 2 2x -2(6 - 3x) = 4 plug into 20 cquation 2x - 2y = 4 coefficients of y are opposite 2x - 12+6X = 4 distribute 8x = 16 add 8x = 16 simplify simplify X=2 3(2)+ y 6 Plug x = 2 back into original 6+y6 X=2 y=0 Solve each system of equations. Use any method. 35. (2x+y = 4 13x +2y = 1 36. (2x+y=4 13x-y=14 37. (2w-Sz=13 6w+32 =10

Answer 1

35 2x+y=4 3U+2y=1. ③ x 2 then subtract from @ get 30+2y=1 40+2y = 8 We -=-7 U=7 Putting in 19; 4 =4-24 24-14=-10 50 a=7 y=-10 36 20+4=4 30-y-ly. Add ① and @ zu+y=4 30-y=14 51 =18 1-18 20-34 -16 5 5 5 Putting in , y=4-20 = 4036 u=18/5 SO 137 26 52=13. 6W+32 =10 0 x 8 then subtract from @ BW +37=10 6W -15% = 39 182= -29 29 + Z- 18 -145+234 89 in O' zW=5z+13= 145 .+13= Putting 89 W = 36 89 W = 36 29 30 2= -2