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A boxer would like to know the mean diameter of a navel orange. If the standard deviation is 0.3 inches, how many oranges wou
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Answer #1

Ans c) 35

Explanation:

Standard deviation \sigma = 0.3

Critical value at 95% confidence: z_{0.05/2} = 1.960

Margin of Error E = 0.1

E = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

n= \left [ \frac{z_{\alpha/2}\times\sigma}{E} \right ]^2

n= \left [\frac{1.96\times0.3}{0.1} \right ]^2

n= 35 ans.

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