Answer: count=28
#include <stdio.h>
int main(void) {
int k,j,count=0;
// And this loop here runs -1 to 5 total a 7 times(-1,0,1,2,3,4,5)
for(k=-1;k<=5;k++){
//this inner loop is going to increase the count 4 times each time
for(j=4;j>=1;j--){ //this is increments the count 4 times(4,3,2,1)
count++;
}
}
Total number of increments are 7*4 so total 24 times
printf("count=%d\n",count);
return 0;
}
#include<stdio.h> sint main() { int k, j, count = 0; for (k = -1; k <=...
#include<stdio.h> eint main() { int i = 0, j = 0; while (i < 10|| j < 7) { i++; j++; } printf("%d, %d\n", i, j); getchar(); return 0; } 01,01 10,10 7.7 10,7
what is output
#include<stdio.h> pint main() { int i, j, total; for ( 2 { printf("\n"); for ( 2 { total = i + j; printf("%d", total); بہا } getchar(); return 0; } Find the for loop content | Output of progrm 5 15 1 11 21 31 41 51 61 2 12 22 32 25 3 13 23 33 43 53 63 4 14 24 34 44 54 64 35 45 6 16 26 36 46 56 66 7...
What is printed when the following code is executed? #include <stdio.h> int main() { for (int i=3, j=5; i>=0; i-=2, j+=j*i) { printf("%d", j); منم }
What is the functionality of the following code? #include #include mainO <stdio.h> <unistd.h> int i,j; j-0: printf ("Ready to fork.n) i-fork; if 0) this code.\n"); printf "The child executes for (i-0; i?5; i++) printf("Child j-dn".j); else j-vaito printf("The parent executes this code. Ln" printf ("Parent j-dn",j);
please help me asap
1 Determine the output for the following code: #include<stdio.h> int main static int num; fornum : ++ num: num++) -- printf("%d". num): if num ==8) break; [10] COI retum 1 b) #include<stdio.h> int main int test: fortest - 0: tests=5: test); printer test: retum
6. Consider the following program: #include <stdio.h> main() { int a,b,c,d ; a=0; while (1) { printf("%d\n", a); printf("Input? "); scanf("%d",&c); if (c == 0) break; d=0; for (b=1; b<=c; b++) if (c%b == 0) d++; if (d == 2 11 C == 1) a=a+c; } } What does this program do? Rewrite the code, organizing it using sound principles. Include comments and redo variable names and indentation. Use multiple functions, blocks, and/or preprocessing if you deem it necessary.
#include<stdio.h> int functionl (int x, int y); int main() int ij=2,k; for(i=1;i<=5; i++) k = function1(ij); printf("k=%d\n",k); return 0; int function] (int x, int y) int z; z=x*2+y; return z;
Question 3 Predict the output of the following C program: #include <stdio.h> void main() { int i = 0; for(; 1; i++){ printf("%d",i); if(i==7) break; } 12pt Paragraph 1 Β Ι Ο Αν και Ta
//countingAnimals.cpp C++
#include <iostream>
#include "Animal.h"
using namespace std;
int Animal::count = 0;
int main(int argc, const char * argv[])
{
Animal myAnimal;
Animal anotherAnimal;
cout << Animal::count << endl;
return 0;
}
1. What is the output of the following program? include <stdio.h> int wilma (int x) if (x<5) x = 7; return (x) int main (void) int x-1 x=wilma (x) ; printf ("%d", x); return (0) b)3 c) 4 d) 7 a) 1 e) none of these