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An 80 kg spool (kg = 0.3 m) is on a rough surface and a cable exerts a 30 N load to the right. The friction force at A acts t

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80 kg spool, KG=0.3 m BON 0.2m 0.75m A 30 30-f= so a 30x (0-2) + f (0.75) = 80% (0.3)²x a f a=0.75a 30-f= 6oa -(1) (17+ 20 6​​​​​​Friction acts towards right, a​​​​G should be directed to the right.

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