Question

Use Loop Analysis to complete the elements of the Amatrix of the equation A*I=S, where A is the nodal matrix, I is the loop currents vector and Sis the sources vector for the circuit below: 13 Z1 212 2/0° 12%ºv + Is Vs 22 T 122 11 Z3j42 24 32/12 v 12 13 Copy the Rxx and paste below then complete. R11= ; R12= ; R13= R21= ; R22= ; R23= R31= ; R32= ; R33=

CIRCUIT ANALYSIS!
Electrical engineering!
Knowledge of MATLAB required!!!!
Professionals only!
Please be clear and concise.
MUST ANSWER ALL PARTS OF QUESTION!!!!!!!! Credit only awarded to all complete answers
Please circle answers

Answer 1

MATLAB PROGRAMME::

clc;
clear all; close all;

%% circuit data
z1=2; z2=-2j; z3=4j; z4=2;
vs=12; is=2;
%% loop analysis
A=[z2+z3 -z3 z1;-z3 z4+z3 0;-1 0 1]; %% mesh analysis matrix
S=[-vs;vs;is]; %% source vector
i=inv(A)*S; %% finding loop currents
vo=i(2)*z4 % output voltage
R=abs(vo) % absolute values of v0
theta=phase(vo)*(180/pi);
disp(['vo=',num2str(vo)]); % this is to display the results
disp(['vo=',num2str(R),'/_',num2str(theta)])

%% noddal analysis
A1=[(1/z1)+(1/z2) 0 -(1/z1);(1/z2) (1/z3) ((1/z1)+(1/z4));0 -1 1]
S1=[-is;0;vs]
node_voltages=inv(A1)*S1

MATLAB RESULTS:

vo =

-1.3333 - 5.3333i

R =

5.4975

vo=-1.3333-5.3333i
vo=5.4975/_-104.0362

A1 =

0.5000 + 0.5000i 0.0000 + 0.0000i -0.5000 + 0.0000i
0.0000 + 0.5000i 0.0000 - 0.2500i 1.0000 + 0.0000i
0.0000 + 0.0000i -1.0000 + 0.0000i 1.0000 + 0.0000i

S1 =

-2
0
12

node_voltages =

-2.4000 + 0.8000i
-11.2000 - 1.6000i
0.8000 - 1.6000i

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