Question

c++ please

Instructions In this assignment, you need to complete following tasks on 2D array of randomly sales figures. Assume that you are the manager of coffee shop chain, and oversee 5 branches. ID of branches are 1 to 5. You already collected sales data for yesterday from each branch, in three categories: morning, afternoon, and evening. First, you need to create a 2D array (5x3) with random numbers between 300 and 1000 (including 300 and 1000), i.e., from $300 to $1000. Then, find / answer • Print the sales data in 5 rows and 3 column format • Show highest sales amount (regardless of time of day and branch) • Show lowest of sales amount (regardless of time of day and branch) Average of sales amount done by shop ID: 3 • Find out which branch make highest sale in the evening. • Is total of all morning sales from all branches higher than total of all afternoon sales from all branches? (Yes/No)

Answer 1

The solution of the given problem is below:

The screenshot of the code is :

1 #include<bits/stdc++.h> 2 using namespace std; 3 int main() srand(time()); 5 int sales[5][3]; int i, j; 7 for(i=1;i<=5;i++) 4-{ 6 8 { for(j=1;i<=3; j++) { int a=rand(); a=(a+300)%1001; sales[i][j]=a; } } 9 10- 11 12 13 14 15 16 17 18 19 20 21 - 22 23 24 cout<<"Your collected sales data in (5*3) matrix is:\n\n"; for(i=1;i<=5;i++) { for(j=1;j<=3; j++) { } cout<<sales[i][j]<<" "; cout<<"\n"; 25 مہ 26 27 cout<<"\n"; int max=0, min=2000; int p, q, arr[5]; 28

for(i=1;i<=5; i++) int sum=0; for(j=1;j<=3; j++) { { if(max<sales[i][j]) { max=sales[i][j]; pri; } 29 30- 31 32- 33 34 - 35 36 37 38 39 40- 41 42 43 44 45 46 47 48 49 if(min>sales[i][j]) catole { min=sales[i][j]; q=i; } sum+=sales[i][j]; } arr[i]=sum; مها 50 51 52. cout<<"Highest sales amount is: "<<max<<endl; cout<<"Lowest sales amount is:"<<min<<endl; cout<<"\n"; int id; cout<<"Enter the shop ID whose average to be find: cin>>id; cout<<arr[id]<<"\n"; int m=0,2; for(i=1;i<=5; i++) ; 53 54 55 56

{ if(m<sales[i][3]) { m=sales[i][j]; z=i; ہا 57 - 58 59- 50 51 52 53 54 55 56 57 58 59 } cout<<"The branch makes the highest sales in evening is: "k<z«<endl; if((sales[1][1]+sales[2][1]+sales[3][1]+sales[4][1]+sales[5][1])> (sales[1][2]+sales[2][2]+sales[3][2]+sales[4][2]+sales[5][2])) { cout<<"Yes"; } else cout<<"No"; cout<<"\n"; 71 72 73 }

The output screen :

Your collected sales data in (5+3) matrix is: 310 387 39 766 172 569 888 117 117 956 625 876 691 265 799 Highest sales amount is: 956 Lowest sales amount is: 39 Enter the shop ID whose average to be find: 3 1233 The branch makes the highest sales in evening is: 4 No

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