Question

need help with these problems. im stuck. please solve in detail and provide your answer. i will rate fast and high

#1

1.-(50) Find: Vas Im I and the region of Ro RG 15V NW 414 geration 60 mA/ 4:2V PG IMA R = 200.2

#2

Answer 1

1 Given: Rolma] Ro=loor #14 is v voi Transistor (MOSFT) operates in saturation region. since, yo=v6 becau IG=0. So, IG RG =0 → Condition, Vos 2 VGs-v to / Z GYS - .vt Condition satisfied. so, MOSFET operates in saturation sol ID = kn [vons-v²

ID kn [vois vt]² kn = 60mA/v2 Vt = 2V .ID = GO MA/z [[ugs-2] ² But VGS 2 on VOT*. 'I. -51 ID = 30mA [ 133 - In 200]? 12 = ID = 30 mA [169+ Io +0000 - 5200 ID] Too 3 ID 169 + Ib? 40000 52000D

- ID2 40000 5233:33 Io +1690 After solving Io = 72.78 mA and 58.84 mA To check the valid root =ON Io 200 root 1 sl=an 14.556 Oo 4 4 root 2 1s 11.6 +3.392 Vos > vt so, root.2 is ore ১৩, ID 58.0 04 MA

VGS = VDs = is - Ig(200) VGS 15 - 200 (58.04 m47) VGS 3.92v. T m [2 kn ID = /2 * somn *58.04MA gm = 16 964.8 mo gm= .83.45 mv > regiona operation is Saturation.

3) 200 22 3V. IMA I M p=200 UBE - For IB KVL to the input Loop. V + (FB+7c) 200+ IB IM TUBE TO Assume UBE = 0.7 - IB ( 1 + B) 200 + 1Mr] =203 ² IB 203 (0.402m+ 1M.)

IB = 1.64 MA ☺ Ic Ic= BIB Ic= 200 (1.64 MA) Ic= 3281MA I c = 328. led calculate UBE and VCE

VCE VCE= Vc -VE VC 3-(Ict IB) 200 3 - (1.64+328-1uA 200 3 - 65.82 mv = 3 ooo6582v. VCE 239341

region ca operation since, VBE LUCE the transistor operates in Active region.