Question

Find the multiplicative inverse of [x + 1] in Q[x]/(x4 + x + 1) Format BIU ...

Answer 1

Find the multiplicative inverse of [x + 1] in Q[x]/(x4 + x + 1) Format BIU ...

solutions (3x4 +86 +1) (3+) (ax? +bx++ox td] +64 +20+1) = 1+6+*+x+1) taxt tbx?tex² + dx taxtbox"textd = 1 axt + (atb) x + (6 +c) x² te tdjxtd=1 (a+b)x² + (btc) oc²+e+d-a)x+ d-a=1 draal atbzo btc=o -atetdzo دل نے 8 OOO R; GRI отт 0 0 - OOO - R₂ R₃ tri R4 R4+RI ooo

R3 R₃-Rq Rk Ru-Ra a o o π o 0 R3 R4 o O o 2) - l dao acada =) =-1 bal=0 16=1 & atbzo = la=n1 then 3 = (boo) = (x²+x²_x [x+1) Ex²+x², Extra = [ext_x_it] [1] 3 -xx to x²_xx3 x . =