Question

A drag racer accelerates at a(t) = 74 ft/s. Assume that v(O) = 0 and s(0) = 0. a. Determine the position function for t20. b. How far does the racer travel in the first 6 s? c. At this rate, how long will it take the racer to travel mi? 3 d. How long will it take the racer to travel 300 ft? e. How far has the racer traveled when it reaches a speed of 180 ft/s? a. The position function for t20 is s(t) = b. In the first 6 s, the racer travels ft. (Simplify your answer. Type an integer or decimal rounded to three decimal places as needed.) 1 c. At this rate, it will take the racer s to travel mi. 3 (Do not round until the final answer. Then round to three decimal places as needed.) d. It will take the racer s to travel 300 ft. (Do not round until the final answer. Then round to three decimal places as needed.) e. When the racer reaches a speed of 180 ft/s, it has traveled ft. (Do not round until the final answer. Then round to three decimal places as needed.)

Answer 1

ful Ginn acto = 74 ftli v Cojo, 301=0. We how a(t) = de adu dtv dt © for position fonction S(H). we have integrate att) two times of a(t) = dg duldt dtv ()= guladt. Now 7= facts.at こ 374-ét. WW= Tut feu COD=0 = 746) tri azo 818 thL=() Now, VALS - 28 thik 2+2 =376ta 3700)+cL C2=0 SCO) 304) - 17tq ft J position fonction

sphor t & uslbf nulla Preporu roedd bo 37 t=6.896 Decents 6 1760 Eat osti nate o Atosti = CAS toof (estsjxq min e (DS 1332 ft. gette 1/ Olete = (of-(0)8 = 88 7sliga Distance travelled in

To reach reach 300 ft. s(t) = 300 I 300 374= 300 3 37 &= 2.847 seconds isi Tim Taken to reach zooft 2.847 seland VE) = 745. 74€ speed, [ from ano 180 = to 180/74 8. Distance travelled in t=180 74 3 (t) =37 180 - 37 | 32400 5476 218.91 ft ... Distance Travelled to reach. 180 f48. speed is 218.91 ft