Question

3. Calculate the maximum temperature of a brass pin with 20 mm x 20 mm cross section sliding on a AISI 1095 steel disk at a relative velocity of 1 mm/s and a high stress of 2 GPa in the dry condition (u = 0.22). Assume that the entire surface of the brass pin contacts the steel surface. Mechanical and thermal properties of the two materials are given below: Material Bulk hardness (GPa) Thermal diffusivity (mm/s) Thermal conductivity (W/m K) Brass Steel AISI 1095 35.3 12.5 115 45 1.93

Answer 1

From the given data, &6-35-2 Kb= 115 W/m-k ks 45 W/mk V = 1 mm/s = 10-3 m/s High stress pa= 2GPa = 2x109 N/m² M=0.22 l = 20mm 10x10-3 (since for square source 22x22) Reference: Introduction to Tribology (Bhushan) (Refer 6.2.15 a and 6.2.156) For square heat source, Am=1.12 Oman - Am q l- Kitk2 Frictional heat q = MPa V = 0.22 424109 x 10 3 - 440 x103 N/m3 Hence, Maximum temperature (fromo) Oman = 1.12 x 440X10 x 10 3x10 30.8K (115+ +5)

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