Question

Under normal operating conditions, the electric motor exerts a torque on shaft AB. Pulleys B, C, and remove torques of 1.86 kN-m, 1.01 kN- m, and 0.67 kN-m, respectively. The bearing at E allows free rotation. Determine the maximum shear stress (in MPa) in section AB of the shaft if dAB=57.4 mm, doc=49.3 mm, dcd=45 mm, and dDE=37.8 mm. Hint: The internal torque from D to E is 0 kN-m and the supplied torque at the motor (point A) is going in the opposite direction of TB. Tc, and Тр. Note: Your answer should include the requested units and be to 2 decimal places. مرك Tc dec deo To doe с D

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Answer 1

Tc TB TO daß= 57,4 mm To= Nm Tc = 1.01 km To=0.67 kNm E 7 c B AB ) kerm 6 = 3.54 x 10 Nam Torque en TAB = Te+Tet To = (1.86+\.01 +0.67 TAB = 3.54 kNm TAB polar moment of Inestia af AB, TAB= I dag 1. x 157.434 mm maximum shear stress in AB TAB = TAB X CAB 3.54x10 6 x 57,4 *(57.414 4 4 - 32 32 JAB 32 CAB= 95.3317764 MPa 95.33 MPa Answer