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You may need to use the appropriate technology to answer this question. Consider the following hypothesis test. Holly - 12 =

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Answer #1

a)

The test statistic is given by:

t=\frac{\overline{x_{1}}-\overline{x_{2}}}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}} =\frac{13.6-10.1}{\sqrt{\frac{5.4^{2}}{35}+\frac{8.8^{2}}{40}}} =2.103

b)

Required degrees of freedom = n_1+n_2-2=35+40-2=73

c)

Since this is a two-tailed test, so the p-value is given by:

\\2\times P(t_{73}>2.103)=2\times 0.019457=0.038914\approx 0.0389

d)

Since p-value is less than 0.05, so we have sufficient evidence to reject the null hypothesis H0.

Reject H0. There is sufficient evidence to conclude that \mu_1\neq \mu_2 .

Hence 3rd option.

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