Question

Solution Stoichiometry: We need to make a 0.250 M sodium carbonate solution. We will use a 100.00 mL volumetric flask. How many grams of solid sodium carbonate should we add to the flask to make the solution? Use 105.99 as the molar mass, report correct sig figs, and use g as the unit.

All multiple parts to the same problem, thank you! :)

Answer 1

We have to make 044 025 m 2 cºn, lution - moleculer mors of Nag coz - 105.99 glonor. . 1000 ml 1 m Nag co₂ = 105.99 g of Nazcoz . 100 mt 0.250 m Nay con 105,99 X 0.250X100'00 Wo Do 1000 gos Naglan Sodiam carbonate 22.64975 g of No, coz Nag con = 2.659 (corrected significant figure) :.2.65 g of solid sodium carbonate should require to prepare too mt 8.250m Nazcoz salutica. Moleculer mass of Calcium chloride z 110.98 g/mol ..1000 ml 1 m Cach 110.98 g of Ca cdr 11078 X 100 X 1.200 si wo mL 0.200m Cach 9 1ooo Calcium Chloride 22.2196 of cael 22.22 g of calls Call Connected significant figure) :.2.22 g of solid calcium chloride should need. C It above two solutions are precipritate is due to mixed, the generated calcium carbonate (cacos • CaCO₃ Moleculer Equation of alone Rx" Conneet Balanced Naz Coz Caq) + CaCl₂ (aq) → CaCo3 (s) + 2Nach (aq)