1)the coimplete cell reactio for ZnlZn2+ ll Cu2+l Cu is Zn(s) + Cu2+(aq) ---------> Zn2+ + Cu
the half cell reactions can be written as
anode:
Zn ------> Zn2+ + 2e
cathode:
Cu2+ + 2e -------> Cu
2) the overall reaction can be written as Pb + Cu2+ -----------------> Pb2+ + Cu
half cell reaction can be written as
anode:
Pb --------> Pb2+ + 2e
cathode:
Cu2+ + 2e ---------> Cu
3)the overall cell reaction is 2Ag+ + Pb --------> Pb2+ + Ag
half cell reaction can be written as
anode:
Pb --------> Pb2+ + 2e
cathode:
Ag+ + e -------> Ag
4))the overall cell reaction is 2Ag+ + Cu --------> 2Ag + Cu2+
half cell reaction can be written as
anode:
Cu -------> Cu2+ + 2e
cathode :
Ag+ + e -------> Ag
- Zn2+ Choose... Choose... (1pts) Identify the complete redox reaction for a ZnZn2+1|Cu2+1Cu cell. A. Zn(s)...
Table view List view Ecell (calculated) Ecell (calculated) 1.115 1.124 Table 1. Voltaic cells data table Ecell (measured) Reaction Quotient Q 1. Zn | Zn2(1.0M) || Cu2+(1.0 M) | Cu 2. Zn | Zn2+(1.0 M) || Cu2+(0.1 M) Cu 1.067 3. ZnZn2+(0.1 M) || Cu2+(1.0 M) | Cu 4. Zn | Zn2+(1.0 M) || Pb2+(1.0 M) | Pb 5. ZnZn2(1.0M) || Pb2+(0.1 M) | Pb 0.600 6. Zn | Zn2+(0.1 M) || Pb2+(1.0 M) I Pb 0.644 7. ZnZn2+(1.0 M)...
Identify the complete redox reaction for a CulCu2+||Ag+Ag cell. A. Cu(s) + Ag(s) Cu2+ (aq) + Ag+ (aq) B. Cu(s) + Ag+ (aq) + Cu2+ (aq) + Ag(s) c. Cu(s) + 2 Ag+ (aq) (aq) + 2 Ag(s) D. Cu²+ (aq) + 2 Ag(s) + Cu(s) + 2 Ag+ (aq) → Cu2+
A galvanic cell consists of a Cu(s)|Cu2+(aq) half cell and a Zn(s)|Zn2+(aq) half-cell connected by a salt bridge. Oxidation occurs in the zinc half-cell. The cell can be represented in standard notation as Cu(s)|Cu2+(aq)|Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu(s)|Cu2+(aq) Cu2+(aq)|Cu(s)||Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s) Zn2+(aq)|Zn(s)||Cu(s)|Cu2+(aq) A,B,C,D?
tion 3 of 40 ) A voltaic cell employs the redox reaction: Zn (s) + Pb2+ (aq) — Zn2+ (aq) + Pb () where Pb2+ (aq) + 2e Zn2+(aq) + 2e Pb(s) E = -0.1262 V Zn(s) E = -0.7618 V The cell potential (Ecell) of this voltaic cell when [Pb2+1 = 1.10 M and [Zn2+) = 0.00110 Mis:
Identify the oxidation half reaction of Zn(s). Select one: O Zn(s) + Cu2+ (aq) → Zn2+ (aq) + Cu(s) O Zn²+ (aq) + 2e + Zn(s) Zn(s) → Zn2+ (aq) + 2 e Zn(s) → Zn2+ (aq) +e
The Standard Cell Potential E0 for the following reaction: Zn(s) + Cu2+ (1M) --> Zn2+ (aq, 1M) + Cu(s) is E0=1.10V. What would be the cell potential E for reaction Zn(s) + Cu2+ (2M) --> Zn2+ (aq, 0.010M) + Cu(s) ? Is it smaller than 1.10V or larger than 1.10V? Explain your answer
Calculate for the reaction: Zn! Zn2+ (0.60M)| |Cu2+ (0.20M)|Cu Given the following: Cu2+(aq) + Zn(s) Cu(s) + Zn2+(aq) Eo-1.10V
1.) For the complete balanced redox reaction below, what is the Eocell? Zn(s) + 2Cu+(aq) ⟶ 2Cu(s) + Zn2+(aq) Zn2+ + 2e- Zn(s) Eo = -0.76 V Cu+ + e- Cu(s) Eo = 0.52 A) -1.28 V B) +1.28 V C) 0.24 V D) -0.24 V E) +2.56 V 2.) For the redox reaction below, what is the Ecell if [Zn2+] = 0.072 M and [Cu+] = 1.27 M? T = 298 K Zn(s) + 2Cu+(aq) ⟶ 2Cu(s) + Zn2+(aq) Half Reactions:...
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: Cu2+(aq) + Zn(s) --> +Cu(s) + Zn2+(aq) Suppose the cell is prepared with 5.20 M Cu2+ in one half-cell and 3.49 M Zn2+ in the other. Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.
1. Zn, Zn2+ || Cu, Cu2+ 2. Cu, Cu2+ || Pt, Fe2+, Fe3+ 5. Zn, Zn2+ || Pt, I-, I2 6. Cu, Cu2+ || Ag, Ag+ 7. Zn, Zn2+ || Ag, Ag+ WRITE DOWN THE OXIDATION REACTION AND REDUCTION REACTIONS FOR THE ABOVE REACTIONS PLEASE