Question

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Question 5 4 pts 5. In a test of hypotheses Ho : u = 578 vs. He : u # 578 at the 101 level of the significance a sample of size 42 produced 7 = 573 and test statistic 2 = -1.311 . the p-value (the observed significance) of the test is about 0.200 0.100 0.190 -0.095 0.095

Answer 1

Q5) Here the test is a 2 tailed test as the alternative hypothesis has a not equal to ($\neq$) sign.

Since the test statistic is negative, we first find the left tailed probability at z = -1.311 and then multiply by 2 to get the 2 tailed probability. At z = -1.311, the left tailed probability = 0.0949.

Therefore the required probability = 0.0949 * 2 = 0.1899   $\approx$     0.19 (Option 3).

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Q6) Here the test is a left tailed test as the alternative hypothesis has a less than (<) sign.

We find the left tailed probability at z = -2.149 .

Therefore the required probability = = 0.0158 $\approx$     0.016 (Option 2).

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