Question

Balance the equation, then determine what volume of a 12M HCl solution is required to produce 3L of H2 (8) at STP if you began with óg of Mg- Mg(s) + HCI-H2(g) + MgCl2 (aq)

Answer 1

+ HCl H₂ ) Mg st t Mgcl2(aq) Balancing the eqo as 'H&Ci is not balanced so Put a infront of the + Mgch Mg + 2HCl H29) so 1 mole of ng will produce 1 mole of H₂ 1 mole of Mg 24.31 gon C molan mass 1 mole of H₂ 22.4L (molan volume) 22.4 L of Hy So 24. 31 go of will produce mg 6 gm of 22.4L will mg produced xogm 24.319 5.52L ..og of mg will produce 5.52 L of H₂ But the question is to prepare 3 L of H₂ • So Here the limiting reagent is Hol & not mg - That means HCl will decide how it of H₂ many will be produce . balanced ego is produced 22.4 Lt of H₂ (re 1 mole of H₂) ot Hel by a moie we can see that from the CSScanned with CamScanner

produced from mole of Hel =) 1 l of H₂ will be 2. 22.4 of H₂ be produced from 2 22.4 x3 -) 3L 0.26 mole of HCL. 12 M HCl we have 0.26 mole volumece)x mol anity mole we need Hol nl of tet 0.26 mole 12 M = Эх 0.02 L 0.26 mole - 12 mole 3L produced to Hal we need 0-022 of of Ha. CScanned with CamScanner