Question

Question 1 3 pts The solution of the Initial-Value Problem (IVP) S (x + y)dx – «dy = 0 is given by 1 y(1) = 0 Oy=det-1 - 1 Oy= < ln(x + y) Oy= (x + y) In x Oy= < In x None of them Question 2 3 pts The general solution of the first order non-homogeneous linear differential equation with variable coefficients dy (x + 1) + xy = e-">-1 equals dx 2 Oy=e* (C(x - 1) + 1], where is an arbitrary constant. O None of them Oy=e-*[C(x + 1) - 1], where is an arbitrary constant. Oy=e" (C(x2 – 1) + 1], where is an arbitrary constant. O yr e-* [C(x2 - 1) + 1], where C is an arbitrary constant.

Answer 1

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