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getting towards the last week of summer semester and i do not understand this question at all. please help! thank you!
Exercise #2 lim nts on. & lx sinxg ln x g) sxz [1, 2] J= csl Scanned with CamScanner
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Answer #1

lim 3 -Х [*sini* Ins. * ) да IP otu on СТ, т lim mo a = 1 З Per (&held ex) dа. flag *) - * sinajt maj* (а) -a-sinca) incas li

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