Question

7. The rod CD is rotating with an angular velocity 0cD = 2 rad/s. Determine: i) The velocity of point and show its direction in the figure below ii) What is the angular velocity of link BC? iii) What is the velocity of points B and E? iv) What is the angular velocity of link AB? (30 points) 0.2 m 0.2 m B E 0.4 m 30° CD= 2 rad/s D

Answer 1

Space diagram 0.2m 0; 2m co E 0.4m wes 300 D space diagram, By drawing the AB= 8cm=0.8m Now let's draw the Insti center diagram,

2 scale lama Qolm I IBC A GOOSE J 300 С B. E 10.4m 0.8m we 'CO 3009 FADA.E and We know the did of Velocity at is LCD at Bis I AB. Inst. Center of link BC lies on the plane drawing perpendicular lines from Vc & The point is I Wede Fs 8 m/s We have V = Texus 0.4 X 2= em 20 رت live joined from Inst. Cented is IBC is the B & where BC = 0.4m bor Ic= tan3o IC=0.4 tan 30 = 0.2309m BC Cos 30 = Вс. BI IB 0.4 Cosao - 0.4618m

TCxus ug where to E Draw a live from I from A ICE IE= Ic²+ CE² го зоол. О. Зо540) 5 We have og sos - V E Вс BE 0.236 P 3-4-64 1 1A4 (s 8 ТВхия — 0 - 4-61&х 3. 444 1 BL V 's = 1 - 6 m/s 0 30 54x 3.4 64 - TEx9 ВС E |-058 E АВxus - - 1.6 = 04xus 2 rad/s Ans. Thank you. All the Best.