Question

5 1 Solve the following system of equations by using the inverse of the coefficient matrix. The inverse of the coefficient matrix is shown. 0 4 4 4 11 1 Niw w 2 2 1 А x - 2y + 3z = -1 3 13 1 -2 y - Z + W = -5 4 4 4 - 3x + 3y - 22 + 5 w = -2 3 5 1 - 1 2y - 32 + W = 3 4 4 4 Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. O A. The solution of the system is (0,0,1). (Simplify your answers.) B. There are infinitely many solutions. The solutions are x = (Use integers or fractions for any numbers in the expression.) , y = and za where w is any real number. C. There is no solution.

Answer 1

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x-2y+32 to.w=-1 0.x +y - Z + W = -5 -3x+3y-22+5w = -2 0.2 +2y-32+ = 3 is the given system of equations It can be written as A.X=B and X - AB 1 -2 o 0 - 3 y 3 2 -2 5 -3 Z -5 - 2 3 1 لا Now, At Be given 114 514 as -YA 0 -3/ % -1/2 - 1/2 -3 -3/4 -2 314 1314 -5/4 -YA 74 so, The solution of the system X=A+B X = -la o -/2 -3 (1/ -3/2 -3/4 514 1/2 13/4 -514 -5 -2 -Ya -2 3/A ya 3 x - = TIT 32-58 +₃ -9 6 34-65/4+%-6 3+27 - 2 +3 = & SN 3 -6 -34 -21 8 and the system's solution Pe unique as Rank A=4 This option (a) to correct The solution the System 4-6),F34.1-21), 18 of