Question

Practice Exercise 11 Name ENGR 115 Week 5 2. The thin ring can be adjusted vertically between three equally long cables from which the 100 kg chandelier is suspended. If the ring remains in the horizontal plane and z = 600 mm, determine the tension in each cable. 0.5 m 120 120 DE 120

Answer 1

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Thanks .. equilibrium 0 0.5 cos 300 = 0 FAD Geometay: Refereeing to the geometry g the quee-body diagram shown in Fig. (a) , the length of cables AB, AC , and As are all e = No.5 + 0.62 No.61 m Equations of equilibrium Ieequires ΣΕ FAD - FacCouscos 300 0.61 10.61 FACE efy -O FAB C0.5 -25 F (0.5 sin 300 = 0 FAB = F Joool No.61 Thus, cables AB, AC, and AD all develop the same tension & Fz = 0; 3H 0.6 100 (9.81) vo.61 FAB = FAC = FAD = 426N Answer 0

곤 C D 0.5m "0.5m L-o.6m 0.5 m 0.6m. 0.56530'm FAD FAC 0.6m FAB 0.551730 mm ř 10019.81)N (a)

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