Question

o The following data represent the percentage of the population that have at least a bachelors degree and the per capita per
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Answer #1

We have to test the claim that regions with higher percentage of the population with atleast a bachelor's degree have higher per capita personal income at 0.05 level of significance.

1) -

Hypothesis -

Null hypothesis - H0 : There is no relationship between bachelor's degree & per capitta personal income. i.e. \rho = 0.

Alternative hypothesis - H0: There is relationship between bachelor's degree & per capitta personal income. i.e. \rho \neq 0.

2) -

Test statistic -

r_{s} = \frac{\sum (x_{i}-\bar{x})(y_{i}-\bar{y})}{\sqrt{\sum (x_{i}-\bar{x})^{2}\sum (y_{i}-\bar{y})^{2} }}

Observation table -

Sr. No. x y (x-x_bar) (y-y_bar) (x-x_bar)(y-y_bar) (x-x_bar)^2 (y-y_bar)^2
1 28.4 33746 3.82 4299.2 16422.944 14.5924 18483120.64
2 24.2 30057 -0.38 610.2 -231.876 0.1444 372344.04
3 25 25158 0.42 -4288.8 -1801.296 0.1764 18393805.44
4 26.6 29372 2.02 -74.8 -151.096 4.0804 5595.04
5 18.7 28901 -5.88 -545.8 3209.304 34.5744 297897.64
Total 122.9 147234 17447.98 53.568 37552762.8

Calculations -

r_{s} = \frac{\sum (x_{i}-\bar{x})(y_{i}-\bar{y})}{\sqrt{\sum (x_{i}-\bar{x})^{2}\sum (y_{i}-\bar{y})^{2} }}

r_{s} = \frac{17447.98}{\sqrt{(53.568)(37552762.8) }}

r_{s} = \frac{17447.98}{44851.1583}

r_{s} =0.389

Test statistic -

r_{s} =0.389

3) -

Rejection region -

r_{s} > 0.879

a normal distribution N 0.01 0.05 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35

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