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Create a new program in Mu and save it as ps3.4.2.py and take the code below...

Create a new program in Mu and save it as ps3.4.2.py and take the code below and fix it as indicated in the comments:

# A year is considered a leap year if it abides by the
# following rules:
#
#  - Every 4th year IS a leap year, EXCEPT...
#  - Every 100th year is NOT a leap year, EXCEPT...
#  - Every 400th year IS a leap year.
#
# This starts at year 0. For example:
#
#  - 1993 is not a leap year because it is not a multiple of 4.
#  - 1996 is a leap year because it is a multiple of 4.
#  - 1900 is not a leap year because it is a multiple of 100,
#    even though it is a multiple of 4.
#  - 2000 is a leap year because it is a multiple of 400,
#    even though it is a multiple of 100.
#
# Write a function called is_leap_year. is_leap_year should
# take one parameter: year, an integer. It should return the
# boolean True if that year is a leap year, the boolean False
# if it is not.

# Write your function here!

# Below are some lines of code that will test your function.
# You can change the value of the variable(s) to test your
# function with different inputs.
#
# If your function works correctly, this will originally
# print False, True, False, and True, each preceded by the
# label "[year] is a leap year:".
print("1993 is a leap year:", is_leap_year(1993))
print("1996 is a leap year:", is_leap_year(1996))
print("1900 is a leap year:", is_leap_year(1900))
print("2000 is a leap year:", is_leap_year(2000))
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Answer #1

Answer:

CODE: Python Programming in Mu

# A year is considered a leap year if it abides by the
# following rules:
#
# - Every 4th year IS a leap year, EXCEPT...
# - Every 100th year is NOT a leap year, EXCEPT...
# - Every 400th year IS a leap year.
#
# This starts at year 0. For example:
#
# - 1993 is not a leap year because it is not a multiple of 4.
# - 1996 is a leap year because it is a multiple of 4.
# - 1900 is not a leap year because it is a multiple of 100,
#    even though it is a multiple of 4.
# - 2000 is a leap year because it is a multiple of 400,
#    even though it is a multiple of 100.
#
# Write a function called is_leap_year. is_leap_year should
# take one parameter: year, an integer. It should return the
# boolean True if that year is a leap year, the boolean False
# if it is not.

# Write your function here!
def is_leap_year(year):
    if(year % 4)== 0:
        if(year % 100 == 0):
            if(year % 400 == 0):
                return True
            else:
                return False
        else:
            return True
    else:
        return False
# Below are some lines of code that will test your function.
# You can change the value of the variable(s) to test your
# function with different inputs.
#
# If your function works correctly, this will originally
# print False, True, False, and True, each preceded by the
# label "[year] is a leap year:".
print("1993 is a leap year:", is_leap_year(1993))
print("1996 is a leap year:", is_leap_year(1996))
print("1900 is a leap year:", is_leap_year(1900))
print("2000 is a leap year:", is_leap_year(2000))
print("2016 is a leap year:", is_leap_year(2016))
print("2020 is a leap year:", is_leap_year(2020))
print("2021 is a leap year:", is_leap_year(2021))

=============================================================================

SCREENSHOT OF THE CODE:

Mu 1.1.0.alpha.2 - ps3.4.2.py + i = ? U Mode New Load Save Run Debug REPL Plotter Zoom-in Zoom-out Theme Check Tidy Help Quit17 18 # Write a function called is_leap year. is_leap year should # take one parameter: year, an integer. It should return th37 # 38 39 40 41 42 # If your function works correctly, this will originally # print False, True, False, and True, each prece

OUTPUT:

Running: ps3.4.2.py 1993 is a leap year: False 1996 is a leap year: True 1900 is a leap year: False 2000 is a leap year: True

Thank you.

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