Question

Question 2 (1 point) Which is the correct Null and Alternate Hypotheses? You want to test whether the average family earns different from $100.000 per year. Ο HO : μ = 100, 000 Η : μ 100, 000 Ο HO : μ 100, 000 Η : μ = 100, 000 Ο HO : μ2 100, 000 Η : μ< 100, 000 Ο Ηo : μ: 100, 000 Η : μ> 100, 000

Answer 1

Solution:-

2. option A.

3. option C.

6. option I. t = -1.75

The provided sample mean is I = 16.8 and the sample standard deviation is s = 4.7, and the sample size is n = 40. (1) Null and Alternative Hypotheses The following null and alternative hypotheses need to be tested: Ho: A = 18.1 Ha: 11 <18.1 This corresponds to a left-tailed test, for which a t-test for one mean, with unknown population standard deviation will be used. (2) Rejection Region Based on the information provided the significance level is a = 0.01, and the critical value for a left- tailed test is te = -2.426. The rejection region for this left-tailed test is R=t:t<-2.426 (3) Test Statistics The t-statistic is computed as follows: X-BO t = 16.8 - 18.1 4.7/40 = -1.749 (4) Decision about the null hypothesis Since it is observed that t = -1.749 > t = -2.426, it is then concluded that the null hypothesis is not rejected Using the P-value approach: The p-value is p = 0.044, and since p = 0.044 > 0.01, it is concluded that the null hypothesis is not rejected. (5) Conclusion It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population mean is less than 18.1, at the 0.01 significance level.

9. option D. 0.07
  
p' = x/n = 21/300 = 0.07

1. option A.