Question

Chapter 10 Section 1 Additional Problem 1 Your answer is partially correct. Try again. Consider the hypothesis test Ho: ui = 12 against Hui <H2 with known variances a = 9 and 02 = 5. Suppose that sample sizes n = 9 and 12 = 15 and that = 14.3 and 12 = 19.5. Use a = 0.05. (a) Test the hypothesis and find the P-value. (b) What is the power of the test in part (a) if u1 is 4 units less than 2? (c) Assuming equal sample sizes, what sample size should be used to obtain B = 0.05 if u 1 is 4 units less than u2? Assume that a = 0.05. (a) The null hypothesis is not rejected. The P-value is 0.0557 Round your answer to four decimal places (e.g. 98.7654). 0.35665 (b) The power is Round your answer to two decimal places (e.g. 98.76). X 67 (c) n = n2 = Round your answer up to the nearest integer.

Answer 1

Answer! The poded variance is given by 10.667 c. 3.266 The test statistic is given by X, --Xq. 14.3-19.5 3.266 Z :- 1592 The p-udue P(2<-1.542) - 0.0557 Thus at level a = 0.05 , we fail to reject the hull hypothesis. Ho and at the level < =0.05 we reject the hull hypothesis if 2<-1-645 under Xit ka < 1.645) & P(x - x 3.266 ' ( X-X+4 3.2GG 4 3-),645+ 3.266 P 3.266 (Z <-1.645+ 4 to 0.9222 alime Equal Sample Size then the pooled varience is 106 C) We 106 n Q=0.05 is 4 Power test *-*9+4 < -1.645+ 100 P Carton <-lous) => (

-1.645+ Hin Sh91 105 2x1.6451105 4 8.468 sil n 코 71.7 Thus hearst integex is n = 71