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Consider the linear system of initial value problems:

0 = Consider the linear system of initial value problems: X Then (1) is: [ 2 3 -1 X with x(0) 41 (a) 2e? - 25 -e? +6e -2e2 +

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Gte2= 0 q=re -3923-7 JIN =-7. 79-662 14 -62-69-14 -7Cq=r14 C2=2. GE-2: 23.-262 +26-57. y = -1 at -1.e 66-5t. 1 (1) = [ - 2e²+х. — 1x x (0) - 3 - 4 -:) у तर 3 - 4 کا ак d-t = +29 9 сo-px??] — ® 3-чу СОтч) 9 - 3х. dy ( de В on both side of we get ( Dr→ [D+3D 407% =0 mit 3m-10 zo m²+5m-2m-1050 (mAh) (0-2) =0 m=2,-5 at -57 te , 9, C are constants 27 st asbitary constants x= g

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