Question

Z= tan" ( 1 ) finds I equation of tangent the plane to this surface aut point where 2, Yol (Hint: arc tan () - itt:) X= 2.distance from the tang ent the origin plane to

Answer 1

1-4f i. Za tan -Z ltat ol lot = tan (2) = tan (3) Since tan (&+B) tañat taniß (ety tansettanity Chry Zla=agai tani et 2) F(x, y, z) tanlettany z Fe=1 7 F (a,l, tan! (33) ltaa ㅗ Fy= Ttya > Fy (2, 1, tan (21) = Ez = -1 > Ę (2, 1, taú (3)) = -1 Equ" of Tangent place at (76, Joze) is Fu (to, goza) (M-76) + fy Glogo, 7 ( g- y) + F Cho ya Z) x (Z-20) / (x-2) + (4-1) - 1 (z-tail2)) = 1 +12 ir So Equh 261-2)+5(4-1)-lo (z-Etani (3)) = Qu+ szloz-4-5-10 tai" (3)=0 2x+5%-loz-q-lo tan (3) - of tangent Distance of tangent plane from origin | 100)+5601-1660)~9-o tan' (3) ] 2²+5+6loje plane 43

1-Atlo tau! (3 aflotan (3) Jaๆ