Question

are justified. 2. Experimental measurements of VLE for a two-component system at 100°C gives the following data: * = 0.30 P (kPa) .21 91 350.0 1.00 1.00 392.7 0.75 0.70 365.0 0.00 0.00 a. (5%) Use Raoult's law to predict the bubble pressure and vapor composition for this system at b. (10%) Using the three points from the table, calculate the coefficients in the 2-parameter Margules equation, assuming the modified Raoult's law is applicable. c. (10%) Using the result from b, predict the bubble pressure and vapor composition for this system at d. (5%) The experimental bubble point for 11 = 0.30 is P = 400.1 kPa and y1 = 0.345. Compare your results from parts a and c to the experimental point. Without knowing what the compounds are, list some potential reasons for the deviations in each case. * = 0.30

Answer 1

Ansir for 1000 at component -1, (a) written as Roult's low can Rips sYzut D -0 and P=ps ar 350 kPa W = 1 Rz=in,=0 ceeasy and cut ni=0; p=p - 365k pa sa at &i=0.3 =) 0.3x350 +0.7 x 365 =p a 30.5lspa and The Sapour will be composition - YIP nps کے

2 - Y,x 360.5 -0.5x 350 Y , = 0.2913 be 360.5hpa and So he bubble pressure liquid contains 29.13% of components 1. One li b) can be marquies (-quation The two parameters written as x2 [ 0 +2 lo y, ha? [A+2(0-A)x) - lore -(A-B) Iz] -4 modified Rower's Equation be written as, can one rips MI Yep r. Yop nips in one dara Second rabie point using the given for Y value me find Can we So, r YIP nips 0.7* 392:7 0.75 x 350

3 = 1.047 Similausily, =) k = YzP nap 0.3x 392.7 0.25X 365 Ibail Now we Vaques par There 11, in one can ☺ 4 my = xez? CAT 2(B-A361) m (10047) = (0.25) ? [A+ 2(0-A) (075)] =) 0.046 -0.0625 A + 0.09375 30.09375 A 0.09375 B -0.03125 A = 0.046 mtz = 6.13+2 (A-B) 423 m (r.291) - (0.75 je l (0.7502 [5+2 (A-3) 10.25)] 0.255 = 0.5625 3 +0.28125 A-0.28125-1 () 3 0.28125 Bt 0.28125 A = 0+255 Bt A = 0.9067 using Calculator Sove © ¢ ® Can for we

0-545 and A = 0.312 we A and get celes les 40 ameless in a-puran murrgueles coefficient so one CIE A = 0.312 and B=0.595 c) using nel marrgueles egn. for composition f first find &, and will 12 е at 2,=0.3, mixture 82 lo so = 2² (ar 2(D-A) &.] ID =) (0.75€ (0.151 0.512 +2 (0.595 -0.512)(0.3) inks =) Y, (0.236) C 997:7 Ell - Similarly ni [3+2 ( A -13) x2] moz =(0.32 {0.595 zews 0.595) (0-7)] tz (0.1312 82 o a179 e 21.018 modi fied Roult's .egn. we (לט plow using the wsite pa nisips + 42 82 pes pe (0-5) (1.260) (350) +(0-7) (1•018 J (365)

p: 343.03MM J: Yiyo, ni Р (p.5) (1.266) () 31 so pre bubble and Vape- 343.0 2 pa pressure COY contains 33.827. of component -1 d) cand TIC one Expesimenten The result from value is compared below a Б Raccuft's modi fied Roured Experimenter Bubble (kpad pressure 360.5 393.03 400 l 29.13% vapouy Composition 33.87 34.5%. mo- e-pure mole alles The experimental values gives higher raue Than dified Rocults because one margueless erameter Guation is applicabic generally been rwhich Chemical nature. size, shape ben Zene cyclohizare so the given -are Similar in and like Air.o2 mixtura may not be following cebove condition.

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