Question

25 (1 Point) Consider the following: CH,COOH + H20 ~ CH,COO + H20+ A buffer solution is prepared by adding NaCH,COO to CH,COOH (aq) When a few drops of NaOH solution are added to the buffer, the equilibrium .... + A. shifts left and [CH,COO) increases. B. shifts left and [CH,COO ) decreases. C. shifts right and (CH COO ) increases. D. shifts right and [CH,COO ] decreases E. doesn't shift and [CH,COO) remains constant OA OB OC OD E

Answer 1

Answer:

When a few drops of NaOH solution are added to the buffer, the equilibrium shifts right and [CH₃COO^-] increases.

Hence, Option C. shifts right and [CH₃COO^-] increases, is the correct answer.

Explanation:

The following reaction is,

CH₃COOH + H₂O $\small \Leftrightarrow$ CH₃COO^- + H₃O⁺

If a buffer solution is prepared by adding NaCH₃COO(s) to CH₃COOH(aq). Then this solution contains equimolar in acid, CH₃COOH and base, NaCH₃COO.

If we add few drops of NaOH solution to the buffer then the reaction is,

CH₃COOH(aq) + OH^-$\small \rightarrow$ CH₃COO^-(aq) + H₂O(l)

So, from the above reaction we can tell that the concentration of [CH₃COO^-] increases, hence the equilibrium position shifts to the right side.