Question

2).

a.
A probability experiment is conducted in which the sample space of the experiment is S = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}, event F= {7, 8, 9, 10, 11, 12}, and event G = {11, 12, 13, 14). Assume that each outcome is equally likely. List the outcomes in F or G. Find P(F or G) by counting the number of outcomes in F or G. Determine P(F or G) using the general addition rule. List the outcomes in F or G. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. For G= {} (Use a comma to separate answers as needed.) B. For G={} Find P(F or G) by counting the number of outcomes in F or G. P(F or G) = (Type an integer or a decimal rounded to three decimal places as needed.) Determine P(F or G) using the general addition rule. Select the correct choice below and fill in any answer boxes within your choice. (Type the terms of your expression in the same order as they appear in the original expression. Round to three decimal places as needed.) A. P(F or G) = + = OB. P(F or G)= + =
b.

Answer 1

n (F) = 6 2) a .. here s s={3,4,5,6,7,8,9,10,11,12,13,143.5(35)=12 F = {7,8,9,10,11,12% G={11,12,13,145 n (6)=4 ForGe contains elements in Fascol wellas elementy in G ié all the elements in both sets For G = {7, 8, 9, 10, 11, 12, 13, 14} in(For G)=8 neForG) 0.66667 P(ForG) = n(s) 8 12 .:: PlFor Q) =10667 By addition Rule pl ForG) - P( 7) + P(G) - PCF and G) here 6 =0.5 PCF) = ACE (5) 12 P(6)= moet toe = 0.3333 Fanda contains elements which appears in both F$ 4 ie common elements Fand 4 = { 11/12) :n(F and 6) = 2 h(F and G) incs 2 - 0:1667 :P(F and 9) = 12

D) 'For with replacement For first card drawn Total no. of outcomes =52 No. of favourable cases = 13 ie noocls spades in standard deck probability of first card is spade is given by P(Spartes) ㅗ for second card drawn first card is replaced back in deck then card is draw from deck : Total no. of outcomes=52 no.of. favourable cases=13 The first card drawn which is spade is replaced back in spade .. deek contains 13 spade cards 13 52 132 4 :: probability of second card is spade is given by P(spade2) = 3 13 14 L 52 ;; probability of both cards are spade is paspade =2) = P(spadez). p(spade 2) YxI 4 16. =0.0625 -0.063 If the sampling is done with replacement, the probability that first card is spade & and card is spade is 10:063