Question

Question 3 (0.5 points) A random variable X has a left-skewed distribution with mean of 50 and standard deviation of 5. Suppo

0 0
Add a comment Improve this question Transcribed image text
Answer #1

No, we can't calculate the probability for the sample mean. Because for the calculating the probability of sample mean the distribution needed must be normal.

Add a comment
Know the answer?
Add Answer to:
Question 3 (0.5 points) A random variable X has a left-skewed distribution with mean of 50...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 2 (0.5 points) A random variable X follows a normal distribution with mean of 50...

    Question 2 (0.5 points) A random variable X follows a normal distribution with mean of 50 and standard deviation of 5. Suppose we take a simple random sample of size 60 from the population above. Can we calculate the probability that the sample mean is between 45 and 60? (You do not need to actually calculate the probability for this question.) Yes, and the calculated probability would be exact. Yes, and the calculated probability would be approximate. No. Question 3...

  • Question 1 (0.5 points) A random variable X follows a normal distribution with mean of 50...

    Question 1 (0.5 points) A random variable X follows a normal distribution with mean of 50 and standard deviation of 5. Suppose we take a simple random sample of size 6 from the population above. Can we calculate the probability that the sample mean is between 45 and 60? (You do not need to actually calculate the probability for this question.) Yes, and the calculated probability would be exact. Yes, and the calculated probability would be approximate. No. Question 2...

  • A population is slightly skewed to the left, has a mean of 50 and a standard...

    A population is slightly skewed to the left, has a mean of 50 and a standard deviation of 7. If a random sample of 28 items are selected from this population, then the mean score of these 28 items is from a sampling distribution that has a standard deviation of ...

  • The original population is severely left-skewed. The sampling distribution of sample mean is A. right-skewed for...

    The original population is severely left-skewed. The sampling distribution of sample mean is A. right-skewed for a sample size of 20 B. left-skewed for a sample size of 20. C. skewed for a sample size of 10 D. approximately normal for a sample size of 100

  • Life expectancy in a country is known to follow a left-skewed distribution with a mean value...

    Life expectancy in a country is known to follow a left-skewed distribution with a mean value of 78.26 years and a standard deviation of 4.29 years. Suppose we take a random sample of 8 members of this country, and calculate their average life expectancy. What is the probably that this sample has an average value of at most 78.52 years? Select one: a. 0.6844 b. 0.9127 c. 0.4800 d. 0.3156 e. We cannot answer this question with the information given.

  • Question number 4: Life expectancy in a country is known to follow a left-skewed distribution with...

    Question number 4: Life expectancy in a country is known to follow a left-skewed distribution with a mean value of 79.66 years and a standard deviation of 3.06 years. Suppose we take a random sample of 15 members of this country, and calculate their average life expectancy. What is the probably that this sample has an average value of at most 79.74 years?

  • 1. Given the probability distribution shown for an infinite population with the discrete random variable, x:...

    1. Given the probability distribution shown for an infinite population with the discrete random variable, x: X: 0 1 2   3 P(X) .2 .05 .3 .45 a. Determine the mean and standard deviation of x. b. For the sample size, n=2, determine the mean for each possible simple random sample from this population. c. For each simple random sample identified in part b, what is the probability that this particular sample will be selected? d. Combining the results of parts...

  • Life expectancy in a country is known to follow a left-skewed distribution with a mean value...

    Life expectancy in a country is known to follow a left-skewed distribution with a mean value of 81.00 years and a standard deviation of 3 30 years. Suppose we take a random sample of 15 members of this country, and calculate their average life expectancy. What is the probably that this sample has an average value of at most 80.97 years? Select one: O 0.3073 b. 0.5517 O c 0.1300 d. 0.4483 e. We cannot answer this question with the...

  • Runtimes at a local marathon are known to follow a left-skewed distribution with a mean of...

    Runtimes at a local marathon are known to follow a left-skewed distribution with a mean of 256 minutes and a standard deviation of 66 minutes if we select a random sample of 57 people, what is the probability that the average run time of this sample will be between 238 516 minutes and 261 245 minutes? Select one a 0.1361 b0 7257 c. We cannot answer the question with the information given Od 0.7030

  • 5. The weights of a shipment of Granny Smith apples follow a right-skewed distribution with mean...

    5. The weights of a shipment of Granny Smith apples follow a right-skewed distribution with mean 185 grams and standard deviation of 13 grams. Using this information, answer the following, if possible. (a) Suppose we take a simple random sample of 6 apples from this shipment. What is the probability that the sample mean weight is less than 180 grams? (b) Suppose we take a simple random sample of 35 apples from this shipment. What is the probability that the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT