Question

4.2 Lateral load Use portal method approximate analysis) to analysis the frame and write down the results in table below Table 3 Lateral load approximate analysis results Membe Normal Shar Momen r End force force t A B BF C CG where P1= 16Kn P2 = 15kn L1 = 7 L2 = 5m L 3 = 6m hl=3m h 2 = 31 le DH EA E EF FE F FE FG FI GF GC G GH HG HO IF - U G

Homework help

Answer 1

SOLUTION 2.5m SEN - 44.akot tom TRN qkN 4 4.२FN 8 k N 4 b 8 KN 15kn 9.846N 5.16kN 7.SIRN at & 2.211kn 4 + 7.9kn 2.53 KN 5.166 10.33 KN +033KA Sifka 10.SEN 10.1kn 2.584 AA 2.211 KN $ - 10.33 5.16 10:33 s.lt T5.5km 1.74 IS.SkNam 5.16 s.id 10.33 10.33 7.74kHT G 97 t d 2.58RN 2.21kN 10.5kn 10llkn * X 7 m. t بصمه 5 m free body dinguam of abructure at of In portal method it is assumed that, Hinge Jorm middle beam & colum Puterior column resist twice ehear force to intosior entrrior colunina compared

JOINI MEMBER END NE ST BM А AE - 2.211 5.16 7.74 B BE lo. S 10.33 is.s C ch lo.il 10,33 is.S D DH 2.58 5.16 7.74 F - 2.211 5.16 -7.74 E 9.84 2.211 7.74 F FE 9.84 2.2 11 7.74 FB lo.s 10.33 -15.5 FG 7.51 7.9 19.75 FI - 4.8 8 12 () GE 7.51 7.9 19.75 G C 10. Il 10.33 -15.5 G H 5.16 2.58 7.74 G J 4.8 8 -12

HG 5.16 2.58 〉tt HD htt- S.16 2.S8 - 12 I 8 TE 48 8 48 12 48 12 J 니다. & 12_ JG 48 4