Question

C++ question

Using a for loop, count the number of even numbers between 1 and a number we supply (inclusive). Return 0 if the parameter is less than 1.

Answer 1

#include <iostream>
using namespace std;
// function declaration
int count1(int x);
int main()
{
// local variable declaration:
int N,res;
cout<<"Enter the number :";                 //enter the number upto which u want to find even number..
cin>>N;
// calling a function ...........
res=count1(N);
cout<<"Number of even numbers :"<<res;
}

// function returning the number of even numbers...
int count1(int x){
int count=0;       
    if(x<1){                            //if number<0 return 0.....
    return 0;
}
else{
    for(int i=1;i<=x;i++){             //number will be even if it is divisible by 2 .....% means modulus will give remainder 0..
    if (i%2==0){
        count++;                      //inrement count....
}}}
return count;
}