Question

15. The average salary in Vancouver has a mean of $70,000 and a median of $48,000. Which statistic would you prefer to use as a measure of center, and why?: * Oa. The mean because this statistic should always be used as the measure of center. Ob. The median because the salaries are strongly skewed left. Oc. The mean because the salaries are bell-shaped. Od. The median because the salaries are strongly skewed right. Questions 16-17: Consider the following summary statistics: Column Median Range Min Max 01 03 n Mean Variance Std. Dev. Std. Err. 10 221.2 127.066666 11.272386 3.5646412 var1 225 36 199 235 210 228 16. What is the range of the data set?:* O a. 18 Ob. 36 Oc. 72 Od. 217 17. Using the boxplot outlier test, any value above _ would be considered a potential outlier.:* O a. 156 Ob. 183 Oc. 255 Od. 282

Answer 1

15.

Option d

Since median < mean, the distribution is positively skewed. Median is better measure if distribution is skewed. Since median is 48000, 50% of population has salary less than or equal to 48000 and remaining have more than 48000.

16.

Option b

Range = maximum - minimum

Range = 235 - 199 = 36

17.

Option C

An outlier is which is greater than Q3 + (1.5*IQR)

Or less than Q1 - (1.5*IQR)

IQR = Q3-Q1 = 228 - 210 = 18

Q3 + (1.5*IQR) = 255 so any value above 255 wold be considered as outlier.