40. What is the pH at the equivalence point for the titration of 30.0mL of 0.43M...

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Answer 1

Answer #1

40. Moles of HCl = Volume * Molariy = 30.0 mL * 0.43 M = 0.03 L * 0.43 mol/L = 0.0129 mol

Moles of KOH = Volume * Molariy = 15.0 mL * 0.86 M = 0.015 L * 0.86 mol/L = 0.0129 mol

At the equivalence point, Moles of HCl = Moles of KOH = 0.0129 mol

So, all the H⁺ ion and OH^- ion combine to form water and the solution is neutral.

So, the pH is 7 at the equivalence point

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Answer 2

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