Question

Info for questions 15 and 16: A pescatarian is a person who eats fish and seafood but no other animal. An event planner does some research and finds that approximately 2.75% of the people in the area where a large event is to be held are pescatarian. Treat the 250 guests expected at the event as a simple random sample from the local population of about 150,000 Question 15 1 pts On average, how many guests would be expected to be pescatarian? Round to the nearest whole person. 1 pts Question 16 Give or take how many? Round to the nearest whole person.

Answer 1

p = proportion of pescatarian people = 2.75 % = 0.0275

n = 250                  ...sample size

15)

Number of guests expected to be pescatarian = n * p = 250 * 0.0275

                                            = 6.875

                                            = 7         ...rounding to nearest whole number

Answer :

    7

-------------------------------------------------------------------------------------------------------------

16)

For finding "give or take" we find the standard deviation s

S= np(1-p) 250 * 0.0275(1 -0.0275)

       = 2.5857

        = 3                 ...rounding to nearest whole number

Answer :

    3

--------------------------------------------------------------------------------------------------------------------
If you are satisfied with the solution, kindly give a thumbs up.