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Reserve Problems Chapter 10 Section 1 Problem 1 Your answer is partially correct. Try again. Consider the hypothesis test Ho

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b)

Point estimate of difference '=x1-x2 = 2.319
for 95 % CI value of z= 1.960 from excel:normsinv((1+0.95)/2)
margin of error E=z*std error = 2.066
lower bound=(x1-x2)-E = 0.25
Upper bound=(x1-x2)+E = 4.39
from above 95% confidence interval for population mean =(0.254 <µ1-µ2<4.385)

c)

rejection region : x1-x2 <=Δ+z*se or x1-x2 >=Δ+z*se or x1-x2 <=-2.0655 or x1-x2>=2.0655
P(Type II error) =P(-2.0655<x1-x2<2.0655 |Δ=3)=P((-2.0655-3)/1.0539<z<(2.0655-3)/1.0539)=P(-4.81<z<-0.89)=0.1867
P(Power) =1-type II error =1-0.1867=0.813
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