Question

A marketing company has randomly surveyed 209 men who watch professional sports. The men were separated according to their educational level​ (college degree or​ not) and whether they preferred the NBA or the National Football League​ (NFL). The results of the survey are shown to the right. Complete parts a through d.

Sports Preference College Degree No College Degree NBA 45 55 NFL 12 97

a. What is the probability that a randomly selected survey participant prefers the​ NFL?

nothing

​(Round to four decimal places as​ needed.)

b. What is the probability that a randomly selected survey participant has a college degree and prefers the​ NBA?

nothing

​(Round to four decimal places as​ needed.)

c. Suppose a survey participant is randomly selected and you are told that he has a college degree. What is the probability that this man prefers the​ NFL?

nothing

​(Round to four decimal places as​ needed.)

Answer 1

Sports preference College Degree No college Degree Totes NBA 45 55 100 NEL 12 97 109 Total 57 152 209 a) P (NFL); P (NFL) # of H Participants who prefer NFL Total # of participants 109 209 = 0.5215 Ars

B) P Ccollege Degree and NBA) The intersectional value of college Degree column and NBA row is 45 which is the # of partiapants who has college Degree and prefer NBA" ::p Ccollege Degree and NBA) 45 209 2 = 0.2153 Ans

11 (6) P (NFL College Degree); P (A/B) is known as Conditional Probability which means that probability of event A given event is occured already" Formula; P(A/B) P (A and B PB) P NFL and college Degree) .: PCNA College Degree P (College Degree Here We already calculated P (NFL and College Deg) = 12 de PC college Degree) 57 209 ::P (NFL College Degree) A 12 209 157 209. 12 57 - 0.2105 Ans