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An artifact dated by C-14 dating would be choose your answer... years old if it had...
The radioactive isotope carbon-14 is used for radiocarbon
dating. The half-life of carbon-14 is years. A wooden artifact in a
museum has a count that is times that found in living organisms.
Estimate the age of the artifact.
The radioactive isotope carbon-14 1s used for radiocarbon dating. The half-life of carbon-14 is 5730 103 years. 14 A wooden artifact in a museum has a C count that is 3.13 x 10 times that found in living organisms Estimate the age...
An archeological artifact was subjected to radiocarbon dating. The artifact showed a carbon-14 decay rate of 12.2disintegrations/min per gram of carbon. Carbon-14 has a half-life of 5715 years, and currently living organisms decay at the rate of 15.3 disintegrations/min per gram of carbon. What is the approximate age of the artifact? Select one: A. 371 years old B. 6597 years old C. 851 years old D. 1867 years old
022 10.0 points The amount of carbon-14 (C) in a wooden artifact is measured to be 25 pern te amount in a fresh sample of wood fro the ane regon Assuming the same amount of carbon-14 was initially present in the artifact, determine the age of the artifact. The half life of carhon 14 is 5730 years. Answerin units of y 023 10.0 points A piece of charcoal used for cooking is found at the remains of an ancient campsite....
Radiocarbon dating techniques are used to determine that a very old piece of bone emits emits about 29 B-particles per sec. If a similarly-sized sample of modern bone emits about 928 B-particles per sec, and the half-life of 14C is 5730 years, approximately how old is this bone fragment (in years)? Submit Answer Tries 0/99
explain 7 & 8 please
Question 7 1 pts The AC activity of an artifact from a burial site was 8.7/min.g C. The half-life of C is 5730 years, and the current activity is 16.1/min.g C (that is, 16.1 disintegrations per minute per gram of carbon). How old in years) is the artifact? Enter number to 1 decimal place. Question 8 1 pts Analysis of an ant found in a piece of amber provided 10 disintegrations of 14C/min.g C, whereas...
Dinosaur fossils are too old to be reliably dated using carbon-14, which has a half-life of about 5730 years. Suppose we had a 66 million year old dinosaur fossit. How much of the living dinosaur's 14c would be remaining today? (Round your agswer to flve decimal places.) % Suppose the minimum detectable amount is O.7 %. What is the maximum age of a fossil that we could date using 14c7 (Round your answer to the nearest integer) Need Help? Read...
QUESTION 2 Radiocarbon dating is used to determine the age of organic materials. Living objects have a consistent amount of carbon-14 in their systems due to the fact that they are constantly incorporating new carbon into their systems and C-14 is being constantly generated by our atmosphere. When an organism dies, it stops incorporating C-14 into its system and the C-14 that was present undergoes a first order kinetic decay. The half life of carbon 14 is 57 15 years...
The radioisotope ¹⁴C (half life = 5730 years) is used for carbon dating. What is the first order rate constant for ¹⁴C?
1. The half-life of carbon-14 is 5730 years. A sample is found to have one-eighth the original amount of carbon-14 in it. How old is the sample? 5730 years, 716 years, 45800 years, 17200 years 2. Why wouldn't you use carbon-14 dating on a piece of shell that was estimated to be 1 million years old? Sea shells do not have radioisotopes, carbon dating is only useful on plants, uranium dating is better for items older than 1/2 million years,...
Carbon-14 is a radioisotope that is used for dating biological organisms. The half-life of C-14 is 5730 years. When a one-gram sample of carbon from fresh peat is measured for radioactivity, 900 beta decays are recorded every hour. A one-gram sample of carbon is obtained from a peat deposit and is measured for radioactivity. If 113 beta decays are observed every hour, how many half-lives of C-14 have passed since the deposit was formed? A. 1/8 B.3 C.113 D.8 Approximately...