Question

(1 point) Healty people have body temperatures that are normally distributed with a mean of 98.20F and a standard deviation of 0.62°F (a) If a healthy person is randomly selected, what is the probability that he or she has a temperature above 99.9°F? answer (b) A hospital wants to select a minimum temperature for requiring further medical tests. What should that temperature be, if we want only 2 % of healty people to exceed it? answer

Answer 1

a) Solution :- Given : Mean (u) = 98.2 Standard deviation (0) = 0.62 P(X> 99.9 ) = 1-P(X< 99.9) = 1- P(x-u /0 < 99.9 -98.2 / 0.62) = 1- P(Z < 2.74) By Using Standard Normal'Z'table, = 1 -0.9969 P(X> 99.9 ) = 0.0031

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b )

is, To find the'z' Score, The'z' distribution of the 2% P(Z > Z) = 0.02 1- P(Z <z) = 0.02 P(Z<z) = 1 -0.02 P(Z < 2.05 ) = 0.98 z Value = 2.05 By Using 'z'Score Formula, X = 2 *O + u X = 2.05 * 0.62 + 98.2 X = 99.47 F

The temperature would be   99 .47 degree F