Question

Calculate the value of the equilibrium constant, Kc , for the reaction Q(g) + X(g) = 2 M(g) + N(g) given that M(g) = 2(g) 6 R

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Answer #1

Lets number the reaction as 0, 1, 2, 3 from top to bottom

required reaction should be written in terms of other reaction

required reaction can be written as:

reaction 0 = -2 * (reaction 1) +1/2 * (reaction 2) +1/3 * (reaction 3)

So,

Kc = (Kc1)^-2 * (Kc2)^1/2 * (Kc3)^1/3

= (3.42)^-2 * (0.496)^1/2 * (11.4)^1/3

= (1/3.42)^2 * (0.496)^1/2 * (11.4)^1/3

= (0.2924)^2 * (0.496)^1/2 * (11.4)^1/3

=0.0855 * 0.704 * 2.25

= 0.135

Answer: 0.135

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Answer #2

the answer to the problem is pi3.1415

source: me
answered by: nbbbbb
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