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Let a T: M2x2(R) + P2(R), 6 d H (2a +b)x2 + (6 – c)x +(c – 3d). с Let B = 9 (6 8), (8 5), (1 3), ( )) (CO 11),( ( 1),66 1 BIs T invertible? (1pt) O Yes O No

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T: M2x2 (IR) P₂ (R) is given by (zatb) x²+ (6-c) x + (1-3d) C d c = (x+2, x+3, x²–2x-6) B is a basis of Max2 (R) containing

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