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Show that there are no three element Boolean Algebras.

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Answer #1

If we define a boolean algebra as having at least two elements, then that algebra has a minimal element as 0 and maximal element as 1 . Each element has a unique complement, i.e., 0 complement =1and 1 complement =0. Let us add a third element y, which is distinct from 0 and 1. It has to have a complement of y as y*, and y* is not equal to 0 or 1 (since y is not equal to 0 or 1). Also, y*≠y(if it were y∨y∗=1 would not hold). So this algebra has 4 elements, and not 3. This is proof about this..

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