Question

 1.  Fill in the blanks in the following C statement such that it allocates memory for an array of 50 character values:

 char *name = (_______ ) malloc(_______ )

 2.  Write a declaration for an array a of 10 strings, each of which has at most 80 characters (including the null character):

 3.  Circle or underline all syntax, logic, and runtime errors found in the following C fragment. Be sure to circle omitted punctuation.

 4. What are two advantages of using recursion in a C program?

 5. Complete the following statements based on this declaration. Assume that the operations are cumulative:

Answer 1

Ans1: char *name = (char *)malloc(50);

Syntax: pointer_variable = (cast-type*)malloc(byte-size)

Ans2: char [10][80];

We have to declare this by using 2d array where 1st dimension is the number of strings and the 2nd dimension is the size of each strings.

Ans3:

char *name_ptr == NULL,name[50] = "Barack Obama", *name2 = "Joe Biden";
name_ptr = name[0];
do
{
printf("Enter a new name: ")
scanf("%c",name_ptr);
}while(name==name2);

1. == syntax error, comparing pointer variable and NULL value instead of assigning NULL value to pointer variable.

2. name_ptr = name[0] error is you are assigning value of name[0] to the pointer but pointer variable is used to store the address of another variable.

3.   printf("Enter a new name: ") there should be semi-colon at the end.

Correct code:

char *name_ptr = NULL,name[50] = "Barack Obama", *name2 = "Joe Biden";
   name_ptr = &(name[0]);
    do
    {
        printf("Enter a new name: ");
        scanf("%c",name_ptr);
    }while(name==name2);

Ans4:

1. Reduces time complexity.

2. Reduces number of unnecessary function calls as recursive function calls itself when it is needed or satisfy some conditions.

Ans5:

1. 6 as strlen function returns the length of the string.

2. The contents of touch[4] is NULL as the touch variable string ends with NULL character which is in 4th index place of string.

3. Positive, as 1st letter of both the string is unmatched at starting so stopping character stops there and stops comparing other characters in the strings. And also the ascii value of 1st character of string 1st is greater than ascii value of 1st character of string 2nd that's why it results positive value.

4. bitt , syntax: strncpy(char *s1, char *s2,size)

strncpy(touch, taste,4) here the string of 4 characters is copied to character touch variable.

5. t , syntax: strncat(char *destination, char *source, size)

strncat(taste,&touch[3],1) so here only 1 character is appended to destination string which is taste character variable.

so after appending the string the result is : bittert

so taste[2] so character 't' is at index 2 position.