Question

Question 2 Water is draining from a pressurized tank as shown in the figure. The exit velocity is given by Ve=(2p/p+2gh)1/2 where p is the pressure in the tank, p is the water density, and h is the elevation of the water surface above the outlet. Constant pressure supply Control surface Exit e The depth of the water in the tank is 1.7 m. The tank has a cross-sectional area of 1.8 m2, and the exit area of the pipe is 20 cm2. The pressure in the tank is maintained at 10 kPa. Find the time required to empty the tank. tpressurized = min Compare this value with the time required if the tank is not pressurized. Enon-pressurized = min

Answer 1

Dato Page Solo- Constant Pressure supply h=17m Ve Exit area *4. 20 X 10 2 A= 20cm2 Volume of water is cylinder or tank Na Axß 118 x 7 m3 V = 3.06 m3 f 2x10x102 Exit velocity For Pressurized tank Ve= (22 +296) Ha + 2*9781x1o7 Ve = 7.3043m/s Watur in tpresurized Volume of tank Nolume flow of water V 3.06 ave 20*104* 7.3043 t pressurized 209.4656 sec = 3.49109 min

Forr Non pressurized (Р- 0) Vo = √29 h - 2x9.81x15 7 =5.775 m/s tnon-pressurized V a vé 3.06 20X10-4 x 50775 = 264.935 min = 4.415 min Inon-pressurized =40415 min It prossurized - 3.49109 min Aus Ary