Homework Answers
It acts as a combination of three capacitors.
C1 = k1*(A/2)*epsilon/(2*d)
= k1*A*epsilon/(4*d)
C2 = k2*(A/2)*epsilon/d
= k2*A*epsilon/d
C3 = k3*(A/2)*epsilon/d
= k3*A*epsilon/d
here C2 and C3 are in series.
so, C23 = C2*C3/(C2 + C3)
= (k2*k3/(k2 + k3))*(A/2)*epsilon/d
C23 is in parallel with C1
so, effective capacitance, C = C1 + C23
= k1*A*epsilon/(4*d) + (k2*k3/(k2 + k3))*(A/2)*epsilon/d
= (A*epsilon/d)*(k1/4 + (1/2)*k2*k3/(k2 + k3) ) <<<<<<<<----------Answer
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