Question

Question A sample of 16 observations is selected from a normal population. The sample mean is 2 wd the population standard deviation is 30 You want to conduct the following test of hypothesis of the 0.05 significance level He w = 300; H. u*300 Calculate the value of the test statistic and submit it as the answer to this question On your submitted numerical calculation page state whether you are Hoor b) do not repect Ho Activate Window Question 66

Answer 1

Answer:

GIven,

Ho : u = 300

Ha : u != 300

test statistic t = (x - u)/(s/sqrt(n))

substitute values

= (294 - 300)/(30/sqrt(16))

= - 0.8

degree of freedom = n - 1 = 16 - 1 = 15

alpha = 0.05

P value = 0.436198

= 0.4362

Here we observe that p value > alpha, so we failto reject Ho.

So there is no sufficient evidence to support the claim.