Question

The bell, which weighs 260 lbs, starts from rest and is hit by a rod (70 lbs) hanging from two ropes. The rod starts from rest at an angle = 45 degrees. Find the angular velocity of the bell and velocity of the rod just after impact. Assume o = 0.6, L1 = 2.5 ft, L2 = 5ft, and the radius of gyration of the bell about its pivot point (A) is 5.4 ft. Hint: be careful with your signs (.e. choose a positive velocity direction and a negative velocity direction and be consistent).

Answer 1

Given! L,000 L2 Tosicoso 0 yod weight of bell, Wb= 200lbs starts from rest iphit by lie. 4₂=0 Wrc 70 lby rod storts from 0:45 given, C-0.6, L = 2.5ft, L₂ = 5 ft rodius of gyration of the bell about pivot point R = 5.9th initial velocity of sod- (4) belonce. loss of potential energy = goin in kinetic energy mg 4/2 (1-60545) I mor Me 9 L, LI-60545) from energy uc 9.81 x 2.5x (1-COS45) 4.85 FHD 0.0250X12 again energy balance loss of potential energy of rod = gain in kinetic energy of the rod now momentum balance mi sms mrxu + Moto = mr y vit mbxy 7074.85 7041+ 2604 Vit 3-2143 V2 = 4.85

Y₂ - Vi 4:35 - 0 ulla. V2 - Y, 2.91 from eq 0 1 0 1.646 youts velocity of rod just offer impact, Y -1.264 $9/) balance How for bell en cog1 ㅗ ! I w my/ 2 2 2 mbkx wb hา 12 1.146 0.3 rad/8 wb = Ongular velocity of Well 5.4 K