The necessary calculation doane below.
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Here n=5,
s=standard deviation = sqrt(sum( d-dbar)^2)/4) = sqrt(16/4)= 2
The 95 % confidence interval for overall average decreases is IQ's for lazy student is given by
( dbar- t(0.025) * s/ sqrt(n), dbar+ t(0.025) * s/ sqrt(n))
(5-2.776* 2/sqrt(5) , 5+2.776* 2/sqrt(5))
(5- 2.4833, 5+ 2.4833)
(2.5167, 7.4833)
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